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18n^2+66n+36=0
a = 18; b = 66; c = +36;
Δ = b2-4ac
Δ = 662-4·18·36
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-42}{2*18}=\frac{-108}{36} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+42}{2*18}=\frac{-24}{36} =-2/3 $
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